This FCKeditor case. When I try customizing Jamit Job Board I got error on admin Page. This error only came on FCKEditor, you can see the error code below

uncaught exception: Permission denied to set property Window.FCK_STATUS_NOTLOADED
....
fckeditor.html (line 183)
uncaught exception: Permission denied to get property Window.FCKeditorAPI

For your attention in our tested case everything run smoothly, but when I test again after my client said they found some error like before I got some error like my client said.

Hmmmm what’s wrong with the code…

I learn every code and html output, everything not on mess, all tag already close. Trying on uncle google an still can’t found anything.

At last I found the problem when I watch every case in before. The problem it’s on HTTP address. In wrong version i used www before the address and the correct setting it’s without www.

For solved the address problem I used .htaccess rewrite

RewriteEngine On
RewriteCond %{HTTP_HOST} ^www.eastafricajobs.com$
RewriteRule (.*)$ http://eastafricajobs.com/$1 [R=301,L]

That’s code will rewrite your url and will redirect www.eastafricajobs.com to eastafricajobs.com

Problem done and one jobs has solved

sebetulnya ini kupipas dari blog sayah *hayoo tebak blog saya apa coba..* berhubung dari kemaren dikejar2 si “luffy” untuk posting,apa boleh buat… *huh!*

Modelling hierarchy data in relational database is hard.

Adjacency list is one of few method to modelling this data to SQL.
if you do not know about adjacency list, or you want to know other method than adjacency list, you might wanto to read Joe Celko’s Trees and Hierarchies in SQL for Smarties

Adjacency list is known with its “easy to insert but hard to retrieve”.

In this post, i want to share my solution on hierarchy data in MySQL with Adjacency list method, in order to have these method work, you need MySQL with TRIGGER support (i use 5.0.45 version).

Lets take a look on dummy data:

Director
|-- Secretary
|
|-- Treasury Mgr
|    |-- Employee 1
|    |-- Employee 2
|
|-- Sales Mgr
     |-- Region 1 Mgr
     |    |-- Employee 3
     |    |-- Employee 4
     |    |-- Employee 5
     |
     |-- Region 2 Mgr
          |-- Subregion A Mgr
          |    |-- Employee 6
          |    |-- Employee 7
          |-- Subregion B Mgr
               |-- Employee 8
               |-- Employee 9

Now, create table

mysql> CREATE TABLE `employee` (
> `emp_id` INT PRIMARY KEY AUTO_INCREMENT NOT NULL,
> `emp_parent_id` INT NULL,
> `name` VARCHAR(200) NOT NULL,
> FOREIGN KEY(`emp_parent_id`) REFERENCES `employee`(`emp_id`)
> ) ENGINE=INNODB DEFAULT CHARSET=UTF8;

Then, to make life easier when retrieving data we need additional table (helper table) : a path table

mysql> CREATE TABLE `employee_path`(
> `emp_id` INT PRIMARY KEY NOT NULL,
> `path` TEXT,
> FOREIGN KEY(`emp_id`) REFERENCES `employee`(`emp_id`)
> ) ENGINE=INNODB DEFAULT CHARSET=UTF8;

after that, we need trigger to automate path builder everytime employee record inserted or updated.

mysql> DELIMITER //
mysql> CREATE TRIGGER `makeEmpTree` AFTER INSERT ON `site`
> FOR EACH ROW BEGIN
>  DECLARE `parent_path TEXT DEFAULT '';
>  SELECT `path` INTO `parent_path` FROM `employee_path` WHERE `emp_id` = NEW.`emp_id`;
>  INSERT INTO `employee_path` VALUES(
>    NEW.`emp_id`,
>    CONCAT(IF(LENGTH(`parent_path`) < 2, '/', `parent_path`), NEW.`emp_id`, '/')
>  );
> END;
> //
mysql> CREATE TRIGGER `updateEmpTree` BEFORE UPDATE ON `site`
> FOR EACH ROW BEGIN
>  DECLARE `old_path` TEXT DEFAULT '';
>  DECLARE `new_path` TEXT DEFAULT '';
>  SELECT `path` INTO `old_path` FROM `employee_path` WHERE `emp_id` = NEW.`emp_id`;
>  SELECT `path` INTO `new_path` FROM `employee_path` WHERE `emp_id` = NEW.`emp_parent_id`;
>  UPDATE `employee_path` SET `path` =
>    REPLACE(`path`, `old_path`,
>      CONCAT(IF(LENGTH(`new_path`) < 2, '/', `new_path`), NEW.`emp_id`, '/') )
>    WHERE LEFT(`path`, LENGTH(`old_path`)) = `old_path`;
> END;
> //
mysql> DELIMITER ;

done!

lets take hands on data:

1st – INSERTING DATA

mysql> INSERT INTO `employee` VALUES
> (DEFAULT, NULL, 'Director'), (DEFAULT, 1, 'Secretary'),
> (DEFAULT, 1, 'Treasury Mgr'), (DEFAULT, 3, 'Employee 1'),
> (DEFAULT, 3, 'Employee 2'), (DEFAULT, 1, 'Sales Mgr'),
> (DEFAULT, 6, 'Region 1 Mgr'), (DEFAULT, 7, 'Employee 3'),
> (DEFAULT, 7, 'Employee 4'), (DEFAULT, 7, 'Employee 5'),
> (DEFAULT, 6, 'Region 2 Mgr'), (DEFAULT, 11, 'Subregion A Mgr'),
> (DEFAULT, 12, 'Employee 6'), (DEFAULT, 12, 'Employee 7'),
> (DEFAULT, 11, 'Subregion B Mgr'), (DEFAULT, 15, 'Employee 8'),
> (DEFAULT, 15, 'Employee 9');

should be returning output such as

Query OK, 17 rows affected (0.01 sec)
Records: 2  Duplicates: 0  Warnings: 0

now, check on path table, it should have content like below:

mysql> SELECT * FROM `employee_path`;
+--------+----------------+
| emp_id | path           |
+--------+----------------+
|      1 | /1/            |
|      2 | /1/2/          |
|      3 | /1/3/          |
|      4 | /1/3/4/        |
|      5 | /1/3/5/        |
|      6 | /1/6/          |
|      7 | /1/6/7/        |
|      8 | /1/6/7/8/      |
|      9 | /1/6/7/9/      |
|     10 | /1/6/7/10/     |
|     11 | /1/6/11/       |
|     12 | /1/6/11/12/    |
|     13 | /1/6/11/12/13/ |
|     14 | /1/6/11/12/14/ |
|     15 | /1/6/11/15/    |
|     16 | /1/6/11/15/16/ |
|     17 | /1/6/11/15/17/ |
+--------+----------------+
17 rows in set (0.00 sec)

2nd – BASIC SELECT QUERY
Get all root nodes
Useful when hierarchy has multiple roots. (This sample has only 1 root)

mysql> SELECT * FROM `employee` WHERE `emp_parent_id` IS NULL;

Get Sibling node
sample query: get sibling of Treasury Manager (id = 3)

mysql> SELECT e.* FROM `employee` e, `employee` e2
> WHERE
>   e.`emp_parent_id` = e2.`emp_parent_id` AND
>   e2.`emp_id` = 3 AND
>   e.`emp_id` <> e2.`emp_id`;

Get Full Tree Nodes From Known Root Node
sample query:get full tree nodes where root is director (emp_id = 1)
Just replace number ’1′ on ‘/1/%’ with another root id if table has multiple root node

mysql> SELECT `emp_id`, `path`
> FROM `employee_path`
> WHERE `path` LIKE('/1/%')
> ORDER BY `path` ASC;

Get Branch Nodes
sample query: get branch nodes of Sales Mgr (id = 6)
Actually, query below is generalization of query above

mysql> SELECT
>  e.`emp_id` AS 'Most Root Node Id',
>  e2.`emp_id,
>  e2.`name`
>  p.`path`
> FROM
>  `employee` e, `employee` e2,
>  `employee_path` p, `employee_path` p2
> WHERE
>  e.emp_id = 6 AND
>  p2.`emp_id` = e.`emp_id AND
>  p.`path` LIKE(CONCAT(p2.`path`,'%')) AND
>  e2.`emp_id = p.`emp_id`
> ORDER BY p.`path` ASC;

Note:
- This query is not optimized!
- This query is generic query, so you could have fun with it.
e.g. : replace ‘e.emp_id = 6′ with :
+ ‘e.`emp_id` = 1′ and you have same result with query “get full tree from known root node
+ ‘e.`emp_parent_id` IS NULL’ and you have all tree grouped by each root node

get hierarchy style
To have hierarchy style we could use query below:

mysql> SELECT
>  e.`emp_id`,
>  CONCAT(
>    REPEAT('  ',
>      (LENGTH(p.`path`) - LENGTH(REPLACE(p.`path`,'/','')),
>      e.`name`
>    ) AS tree
> FROM `employee` e
> LEFT JOIN `employee_path` p ON e.`emp_id` = p.`emp_id`
> ORDER BY p.`path ASC;

+--------+---------------------------+
| emp_id | tree                      |
+--------+---------------------------+
|      1 |     Director              |
|      2 |       Secretary           |
|      3 |       Treasury Mgr        |
|      4 |         Employee 1        |
|      5 |         Employee 2        |
|      6 |       Sales Mgr           |
|     11 |         Region 2 Mgr      |
|     12 |           Subregion A Mgr |
|     13 |             Employee 6    |
|     14 |             Employee 7    |
|     15 |           Subregion B Mgr |
|     16 |             Employee 8    |
|     17 |             Employee 9    |
|      7 |         Region 1 Mgr      |
|     10 |           Employee 5      |
|      8 |           Employee 3      |
|      9 |           Employee 4      |
+--------+---------------------------+

17 rows in set (0.00 sec)

3rd. Manipulating Node
To know whether those query below success or not, you could check yourself by comparing the result from “hierarchy style query” before and after execute each query below.
Move leaf node to another node
Sample query: move employee 3 to treasury Mgr

mysql> UPDATE `employee` SET `emp_parent_id` = 3 WHERE `emp_id` = 8;

Move leaf node to become root node
Sample query: make Region 2 Mgr become a root node (actually, IMO, this action should not happen in the context of employee ;p )

mysql> UPDATE `employee` SET `emp_parent_id` = NULL WHERE `emp_id` = 11;

Move branch node to another branch
Sample query: move Subregion A Mgr to Sales Mgr

mysql> UPDATE `employee` SET `emp_parent_id` = 6 WHERE `emp_id` = 12;

4th. Note

Testing can only prove the presence of bugs, not their absence.
–Edsger W. Dijkstra

This appoarch, of course, have a limitation.
Limitation, or bug, i know was (please share, if you found another limitation/bug) :

• There is no checking when moving a node to its decendant. (I’m still thinking about check whether the new parent node is its decendant or not in before update trigger)
• This approach does not cover node weight yet.(if you have no idea about weight, take a look at “hierarchy style” query result and compare it with sample hierarchy on the top. and ask to yourself, why Region 1 Mgr on the result become below Region 2 Mgr? ;p)

PS: I found postgresql developer wrote about another different approach of adjacency list in his blog. you might want to read about it.

CSS :

#button {
font-weight: bold;
border: 2px solid #fff;
}

PHP :

<?php echo 'hello world!'; ?>

SQL :

SELECT a.* FROM a LEFT JOIN b ON a.id=b.a_id;